15a^2-4a=3

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Solution for 15a^2-4a=3 equation:



15a^2-4a=3
We move all terms to the left:
15a^2-4a-(3)=0
a = 15; b = -4; c = -3;
Δ = b2-4ac
Δ = -42-4·15·(-3)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-14}{2*15}=\frac{-10}{30} =-1/3 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+14}{2*15}=\frac{18}{30} =3/5 $

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